Question
An express subway train passes through an underground station. It enters at t = 0 with an initial velocity of 23.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station in 210 m long.
(a) How long is the nose of the train in the station?
(b) How fast is it going when the nose leaves the station?
(c) If the train is 130 m long, at what time t does the end of the train leave the station?
(d) What is the velocity of the end of the train as it leaves?
Additional Materials
(a) How long is the nose of the train in the station?
(b) How fast is it going when the nose leaves the station?
(c) If the train is 130 m long, at what time t does the end of the train leave the station?
(d) What is the velocity of the end of the train as it leaves?
Additional Materials
Answers
Lydia
(a) use d=vi*t+0.5*a*t^2
manipulate the equation to solve for t
210 m = (23 m/s)t+0.5(0.150 m/s^2)*t^2
t = 9.41 s
(b) v = d/t
= 210 m/ 9.41 s
= 22.3 m/s
I'm still trying to figure out the rest...
manipulate the equation to solve for t
210 m = (23 m/s)t+0.5(0.150 m/s^2)*t^2
t = 9.41 s
(b) v = d/t
= 210 m/ 9.41 s
= 22.3 m/s
I'm still trying to figure out the rest...
Bladimir
3.60