Asked by Babygirl
A subway train is traveling at a rate of 22.4 m/s. Brakes are applied and it slows down at a constant rate of 3.5 m/s^2 until it stops at a station. Find the total distance traveled while braking.
72 m
142 m
274 m
163 m
A cyclist is stopped at a traffic light. When the light turns green, the cyclist accelerates at 3.2 m/s^2. After 2.4 seconds, what is the cyclist’s speed?
15 m/s
7.7 m/s
5.6 m/s
0.75 m/s
Please help guys!
72 m
142 m
274 m
163 m
A cyclist is stopped at a traffic light. When the light turns green, the cyclist accelerates at 3.2 m/s^2. After 2.4 seconds, what is the cyclist’s speed?
15 m/s
7.7 m/s
5.6 m/s
0.75 m/s
Please help guys!
Answers
Answered by
scott
braking time = initial velocity / acceleration
distance traveled = (initial velocity / 2) * braking time
speed = acceleration * time
distance traveled = (initial velocity / 2) * braking time
speed = acceleration * time
Answered by
Babygirl
So the first one would be...
22.4/3.5 = 6.4
22.4/2 = 11.2 • 6.4 = 71.68 = 72
So 72 should be the answer right?
22.4/3.5 = 6.4
22.4/2 = 11.2 • 6.4 = 71.68 = 72
So 72 should be the answer right?
Answered by
Babygirl
By the way, thanks so much for providing the formulas! My lessons don’t even give me the formulas, so I never know what to do.
Answered by
Babygirl
For the second one...
3.2 • 2.4 = 7.68 = 7.7m/s
Would that be correct?
3.2 • 2.4 = 7.68 = 7.7m/s
Would that be correct?
Answered by
Babygirl
Could you help with this as well?
The “reaction time” of the average automobile driver is about 0.7 s. (The reaction time is the interval between the perception of a signal to stop and the application of the brakes.) If an automobile can slow down with an acceleration of 12 ft/s^2 compute the total distance(in feet) covered in coming to a stop after a signal is observed from an initial velocity of 55 mi/h. Let 1 mi/h= 1.466 ft/s.
271 ft
327 ft
113 ft
414 ft
The “reaction time” of the average automobile driver is about 0.7 s. (The reaction time is the interval between the perception of a signal to stop and the application of the brakes.) If an automobile can slow down with an acceleration of 12 ft/s^2 compute the total distance(in feet) covered in coming to a stop after a signal is observed from an initial velocity of 55 mi/h. Let 1 mi/h= 1.466 ft/s.
271 ft
327 ft
113 ft
414 ft
Answered by
bobpursley
yes on both.
Answered by
Babygirl
Thanks! Can you help with the other question I posted?
Answered by
Henry
1. V^2 = Vo^2 + 2a*d = 0,
(22.4)^2 - 7*d = 0,
d = 71.7 m(72m).
(22.4)^2 - 7*d = 0,
d = 71.7 m(72m).
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.