Asked by Douchan

A subway train starts from rest at a station and accelerates at a rate of 1.60m/s^2 for 14.0 s. It runs at constant speed for 70.0 s and slows down at a rate of 3.50m/s^2 until it stops at the next station.

What is the total distance covered?

Answers

Answered by bobpursley
distance:
first leg: avg velocity= 1/2 1.6*14
second leg: avg velocity = 1.6*14
third leg: avg veloctiy= 1/2 * (1.6*14)

multiply each of these by the time for the leg, then add the distances.
Answered by bobpursley
the time for the last leg can be found from Vf=Vi+at...
Answered by Douchan
I am really confused as to what you are doing here.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions