RIGHT, well this might be a bit late but i'm another physics student and just found the solution.
Basically you want to take your current from part A - and your resistance from part B, plug them in into the equation P = I^2R and then subtract your answer from the original power. i.e. 100kwatts
100000W of power is delivered to the other side of a city by a pair of power lines with the voltage difference of 15000V.
a) how much current flows in the lines?
100000/15000 = 6.9 A
b) Each of the 2 lines has a resistance of 10 ohms. What is the voltage change along each line?
6.9 x 10 = 69
c)How much power is wasted as heat in both lines together?
how on earth do you do part c ? help would be appreciated. thanks!
You punched a wrong button somewhere for 100,000/15,000. I have 6.67.
That slight difference will change answer b a little.
c. Power = I2R
Where I is current in amperes and R is resistance in ohms.
Thank you!
4 answers
scratch that - no subtraction. just your answer as it is i think
i meant to say voltage and use the equation P = IV - then multiply by 2 since it's both lines KBAI
69420
4 answers