Your umpteen posts have been removed.
Once you write up YOUR ATTEMPT at each problem, please re-post, and someone here will be happy to comment.
The power P delivered to a load by a current of i amperes through a resistance of 19 ohms, when 110 volts are supplied at one end of the line, is given by the formula P = 110i - 19i2 . Determine the maximum power that can be delivered.
maximum power in watts =
4 answers
Oh, sorry I didn't realise that I needed to provide my answer. I just want to check to see if I obtain the correct answer.
My answer is:
P=110i-19i^2
P'=110-38i
0=110-38i
i=2.8947
P"=-38 therefore a max
Max Power in watts = 2.8947
My answer is:
P=110i-19i^2
P'=110-38i
0=110-38i
i=2.8947
P"=-38 therefore a max
Max Power in watts = 2.8947
Please re-post your questions along with your answers, and a math teacher will check your work.
Also there's no need to switch user names.
Also there's no need to switch user names.
Hmmm. I agree with i at 2.89 amps
Powermax=put i in the formula for power given, and you have it.
Powermax=put i in the formula for power given, and you have it.