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The power P delivered to a load by a current of i amperes through a resistance of 19 ohms, when 110 volts are supplied at one e...Asked by Ashley
The power P delivered to a load by a current of i amperes through a resistance of 19 ohms, when 110 volts are supplied at one end of the line, is given by the formula P = 110i - 19i2 . Determine the maximum power that can be delivered.
maximum power in watts =
My Answer:
My answer is:
P=110i-19i^2
P'=110-38i
0=110-38i
i=2.8947
P"=-38 therefore a max
Max Power in watts = 2.8947
can you please confirm this is correct. Thanks
maximum power in watts =
My Answer:
My answer is:
P=110i-19i^2
P'=110-38i
0=110-38i
i=2.8947
P"=-38 therefore a max
Max Power in watts = 2.8947
can you please confirm this is correct. Thanks
Answers
Answered by
Steve
no, maximum power is P(2.8947) = 159.211
Answered by
Ashley
ok. I understand that you took the value and plugged in for i. But can I ask why...
Answered by
Steve
because they asked for maximum power, not the current which produces maximum power. Just because you arrive at an answer, that does not mean you have answered the question.
Answered by
Ashley
Ok.... great. thank you Steve. I know understand!
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