Question

1) Factorise x2 -6x +8 (the 2 is squared)

2) Hence solve this equation: x2 -6x +8 = 0


Also, what would the line look like on a graph with the equation y = 10/x

Thankyou =)


1) x^2 - 6x + 8 factors are: (x - 2)(x - 4) -->look for possible factors of 8 and determine what will fit to get the middle coefficient of -6. Factors of 8 that fit are -2 * -4. Use FOIL method to check.

2) Now that you have the factors, you can solve the equation x^2 - 6x + 8 = 0
Factored: (x - 2)(x - 4) = 0
Set each factor equal to 0, and solve for each x. You will have 2 possible solutions to this equation.

You can determine what the line would look like for the equation y = 10/x by using a graphing calculator, or by substituting values for x and solving for y. Make sure you get enough points to show the line.

I hope this will help.

If you don't see it, reason as follows. A factorization of an expression like

x^2 -6x +8

is, of course, valid for all values of x. The usual rule of finding two numbers that when multiplied give 8 (and added give -6) amounts to considering the special case x = 0.

But 8 has many factors, so you could try to substitute some other number. If we have a factorization:

x^2 -6x +8 = (x + a)(x + b)

For x = 0 this gives

8 = a*b

But there are many possibilities in this case.

For x = 1 you get:

3 = (1 + a)*(1 + b)

The sum of a and b must be -6. You find the solution by using the factorization 3 = -1*(-3) and you find a = -2 and b = -4

For the function y = x2 - 6x + 8, perform the following tasks:
a)