Asked by Greg
How do you factorise
-13x^2+113x-22
-13x^2+113x-22
Answers
Answered by
drwls
That polynomial does not factor simply.
The roots of -13x^2+113x-22 = 0
are real numbers, since b^2 - 4 ac = 11625. The expression can be written
-13(x- A)(x-B), where A and B are
A = (-113 + sqrt 11625)/-26 = 0.19926
and
B = (-113 - sqrt 11625)/-26 = 8.49305
-13x^2+113x-22 =
= -13(x-0.19926)(x-8.49305)
= (-13x+2.59038)(x-8.49305)
The roots of -13x^2+113x-22 = 0
are real numbers, since b^2 - 4 ac = 11625. The expression can be written
-13(x- A)(x-B), where A and B are
A = (-113 + sqrt 11625)/-26 = 0.19926
and
B = (-113 - sqrt 11625)/-26 = 8.49305
-13x^2+113x-22 =
= -13(x-0.19926)(x-8.49305)
= (-13x+2.59038)(x-8.49305)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.