Asked by Joshua

Factorise as far as possible into Prime Factors:

5x^8 - 80y^4

Answers

Answered by Reiny
first factor out a 5

5(x^8 - 16y^4)

now you should see a difference of squares

5(x^4 - 4y^2)(x^4 + 4y^2)
and once more

5(x^2 - 2y)(x^2 + 2y)(x^4 + 4y^4)

Answered by drwls
I believe Reiny meant to write
5(x^2 - 2y)(x^2 + 2y)(x^4 + 4y^2)
for the last step. The last y exponent is 2.
Answered by Reiny
thanks drwls for catching that.

Time to get new reading glasses at the "Dollar Store", lol
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