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Questions (4)
The shaft ABC is a solid circular cylinder of constant outer diameter 2R and length 3L. The shaft is fixed between walls at A
11 answers
783 views
Q2_1_2 Answers
1) (TCX+2Lt0)/(G0I) where TCx=-t0L/3 2) t0(3L-x))/(2G0I) 3) x=3L
18 answers
666 views
What is the heat of combustion of ethane, C2H6, in kilojoules per mole of ethane?
2 answers
3,231 views
whaqt is an intentional tort
2 answers
447 views
Answers (35)
according to my calculations the answer is 100% 434 🤓
perimeter mean the length of all the sides combined, which in your case is 8. since each side of a square is the same the same length your answer for one side will be the same for the other side. basically 8/4 sides= will give the answer for 1 side which
in my opinion i think 2nd one is correct but the correct was to say it would have been something like " the boy walked along the sidewalk safely"
Excessive bail shall not be required, nor excessive fines imposed, nor cruel and unusual punishments inflicted *****(hint) google search. avoid Wikipedia.
do you mean social studies (hint) **bill of rights**
4n
300N
Q2-1-1 TXC=-t_0*L
Q2_1_2 a) T(x) in 0>> x=2*L answer x=2*L
Q2_1_2 a) T(x) in 0>> x=2*L answer x=2*L
yes, I got a green check.
Q2_1_1 TXC=-t_0*L Q2=1_2 a) 0 (2*t_0*L)/(pi*G_0*R4) b)L(2*t_0*(2*L-))/pi*G_0*R^4) c) x=2*L
Answers Q2_1_2 a) T(x) in 0>> x=2*L answer x=2*L
Answers Q2_1_1 TXC=-t_0*L
I'm waiting your answers, to follow with next items.
Is it correct ? If yes I will going with the second
OK Let me see Answer Q2_1_1: Sum=0 -Tx_1+INTEGRAL{3L-L}t_0*dx+TXC=0 so Tx_1=2*L*t_0+TXC {0
Where I can see images of the problems ?
Q2_1_2 Answers 1) (TCX+2Lt0)/(G_0I) where TCx=-t_0L/3 and I=pi*R^4/2 so answer: (2*TCX+4*L*t_0)/(G_0*pi*R^4) 2) t0(3L-x))/(2G0I) where I=i*R^4/2 so answer: ((t_0*(3L-x))/(pi*R^4) 3) x=3L
Let me know if solutions are correct to go with the next problems.
I need to know if this information is correct, because I solved the problems without correspondent images
Q2_1_1 Answer TCx=-t0L/3
Q2_1_2 1) (TCX+2Lt0)/(G0I) where TCx=-t0L/3 2) t0(3L-x))/(2G0I) 3) x=3L
Q2_1_1 TCx=-t0L/3
Q2_1_2 1) (TCX+2Lt0)/(G0I) where TCx=-t0L/3 2) t0(3L-x))/(2G0I) 3) x=3L
Q2_1_2 for0¡Üx
Q2_1_1 TCx=-t0L/3
Q2_1_1 TCx=-q0L/3
8.4 - 2 = 6.4
preshate it
jnhgy
is superman the best
i just learned this in school today my teacher said the same thing you did that it is not necessary.
give me your number and i will lmao. you stupid
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