Question

Q2_1_2 Answers
1) (TCX+2Lt0)/(G0I) where TCx=-t0L/3
2) t0(3L-x))/(2G0I)
3) x=3L

Answer 1

Q2_1_1 Answer
TCx=-t0L/3

Answer 2

I need to know if this information is correct, because I solved the problems without correspondent images

Answer 3

Let me know if solutions are correct to go with the next problems.

Answer 4

I put this Q2_1_1 Answer but the answer its wrong i put this -t_0*(L/3) and the answer is wrong

Answer 5

Q2_1_2 Answers
1) (TCX+2Lt0)/(G_0I) where TCx=-t_0L/3
and I=pi*R^4/2 so answer:
(2*TCX+4*L*t_0)/(G_0*pi*R^4)
2) t0(3L-x))/(2G0I)
where I=i*R^4/2 so
answer: ((t_0*(3L-x))/(pi*R^4)
3) x=3L

Answer 6

Where I can see images of the problems ?

Answer 7

here
imagehousing. com /imageupload.php?id=1149147

Answer 8

ww.imagehousing. com/imageupload.php?id=1149147

Answer 9

OK Let me see Answer Q2_1_1:
Sum=0
-Tx_1+INTEGRAL{3L-L}t_0*dx+TXC=0
so Tx_1=2*L*t_0+TXC {0<=x<=L}

-Tx_2+INTEFRAL{3L-x}t_0*dx+TXC=0
so Tx_2=t_0*(3L-x)+TXC {L<=x<=3L}

d*phi/dx =Tx/GI

so in x<=_x<=L
d*phi/dx= (TXC+2*L*t_0)/G_0*I

in L<=x<=3L
d*phi/dx= (t_0*(3L-x)+TXC)/(2G_0*I)


in x=3l Phi=0

so

0=INTEGRAL{0,L}(TXC+2*L*t_0)/G_0*I+INTEGRAL{L,3L}(t_0*(3L-x)+TXC)/(2G_0*I)

0=(3*L*TXC+3*L^2*t_0)/(g_0*I)

TXC=-L*t_0


Ok, I believe that this is the correct answer for Q2_1_1


Solving for TXC
TXC=

Answer 10

Is it correct ? If yes I will going with the second

Answer 11

I'm waiting your answers, to follow with next items.

Answer 12

TXC=-L*t_0, its wrong!

if can you help!!

tnks!

Answer 13

TXC=-3/2*t_0*L

Answer 14

Q2_1_2:
d*phi/dx = (t_0*L)/(pi*G_0*R^4)
d*phi/dx = (t_0*(3*L-2*x))/(2*pi*G_0*R^4)
x0 = 3/2*L

some one for the rest?

Answer 15

Q2_1_3:
rômax = R
xômax =3*L

Answer 16

access is your answers are ok, then
Q2_1_3

a) shear stress mx=(4*t_0*L)/(pi*R^3)

Is it ok?

Answer 17

Q2_1_1
TXC=-3/2*t_0*L

Q2_1_2:
d*phi/dx = (t_0*L)/(pi*G_0*R^4)
d*phi/dx =t_0*(3*L-2*x))/(2*pi*G_0*R^4)
x0 = 3/2*L

Q2_1_3:

tau max=(4*t_0*L)/(pi*R^3)
r tau max = R
x tau max =3*L


•MITx: 2.01x - ElementarySchoolStudent, Saturday, July 27, 2013 at 2:12am
Q2_1_1
TXC=-3/2*t_0*L

Q2_1_2:
d*phi/dx = (t_0*L)/(pi*G_0*R^4)
d*phi/dx =t_0*(3*L-2*x))/(2*pi*G_0*R^4)
x0 = 3/2*L

Q2_1_3:

tau max=(4*t_0*L)/(pi*R^3)
r tau max = R
x tau max =3*L



Q2_1_4

1) phi=(9*t_0*L^2)/(2*pi*G_0*R^4)
2) x phi max=3*L/2


I have only one more chance, please help me and tell me if this answers I put here are ok.

Answer 18

Q2_1_4

A little error when I got out a factor of 2, I put it in the numerator and must be in the denominator so the correct answer is.

1) phi=(9*t_0*L^2)/(8*pi*G_0*R^4)


Q2_1_3:

This is the correct answer 3 instead of 4. I added wrong.

1) tau max=(3*t_0*L)/(pi*R^3)