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Questions (36)
Assume there is a large frictional force acting on the cart (coefficients of friction 𝜇𝑆 = 0.4 and 𝜇𝑘 = 0.15), and
1 answer
562 views
Assume there is a large frictional force acting on the cart (coefficients of friction 𝜇𝑆 = 0.4 and 𝜇𝑘 = 0.15), and
1 answer
478 views
Block A with mass 4.0 kg, sits on a friction less table. Block B, with mass 2.0 kg, hangs down from a rope connected through a
1 answer
944 views
Provide an example for an object that experiences each of the following:
A. An object with non-zero velocity and zero
1 answer
395 views
Provide an example for an object that experiences each of the following:
A. An object with zero velocity and zero acceleration B.
1 answer
385 views
Bob accelerates away from a stop sign. His teddy bear is on the passenger seat. On whom does the back of the seat exert a
0 answers
500 views
An object moves in a straight line at a constant speed. Is it true that here must be no forces of any kind acting on this
1 answer
1,452 views
Use a free body diagram to evaluate the situation. What is the tension in each of the ropes attached to the ceiling if the
0 answers
783 views
Now 3 girls are pushing the box each with
the same force. Draw a free body diagram for the box and a-t, v-t, x-t diagrams.
1 answer
514 views
A girl is pushing a box with constant velocity through her
room. Draw a free body diagram for the box and a-t, v-t, x-t diagrams.
3 answers
579 views
A ski jump's velocity can be calculated (assume no friction).
The tower is 60.0m high and the skier is at the bottom, who will
1 answer
826 views
A ball within an initial velocity of 5.55 m/s is shot at an angle of 30 degree above the horizontal using a launcher. The
1 answer
589 views
A ball is rolling with an initial velocity of 5.55 m/s over a table moves over the edge and falls to the ground. How long is the
1 answer
571 views
You are in a car that is traveling along a highway at a constant speed of 16 m/s. Suddenly you see a truck also traveling at a
0 answers
633 views
Consider the following electrochemical cell:
Pt(s) | Hg2^2+ (0.800M) || MnO4^- (0.650M), H^+ (1.00M), Mn^2+ (0.375M) | Pt(s)
4 answers
684 views
From the following reduction potentials, determine the reduction potential of SN^4+ + 4e^- --> Sn^o
SN^2+ + 2e^- --> Sn^o |
2 answers
551 views
Draw a cell diagram to show how you could determine the Kf of [Ni(NH3)5]^2+ using electrochemical cells.
2 answers
465 views
When K is measured for a reaction, the values obtained are 3.1 at 25°C and 7.42 at 35°C. Using the equation
0 answers
370 views
When K is measured for a reaction, the values obtained are 3.1 at 25°C and 7.42 at 35°C. Using the equation
1 answer
395 views
Only 0.0640 grams of PbF2 will dissolve in 100.0 mL of solution. From this data, calculate the Ksp by two methods.
3 answers
517 views
Would your calculated Ksp value be greater, less, or the same, if the following occurred, please explain your reasoning.
a. The
3 answers
576 views
When K is measured for a reaction, the values obtained are 3.1 at 25°C and 7.42 at 35°C. Using the equation
1 answer
498 views
The solubility of lead (II) chloride in water is 4.50 g/L at 25 degrees C
a. What is the molarity of Pb2+ in a saturated solution
1 answer
839 views
A solution contains 0.010 M BaCl2. Calculate the molarity of the ions in solution, the ionic strength of the solution, the
9 answers
1,258 views
Consider the titration of 10.00 mL of a 0.250 M aqueous solution of ethylenediamine (H2NCH2CH2NH2) with 0.250 M HCl(aq). pKb1 =
7 answers
899 views
Consider the titration of 10.00 mL of a 0.250 M aqueous solution of ethylenediamine (H2NCH2CH2NH2) with 0.250 M HCl(aq). pKb1 =
6 answers
669 views
A solution contains 0.010 M BaCl2. Calculate the molarity of the ions in solution, the ionic strength of the solution, the
1 answer
612 views
If 35.00 mL of 0.25 M NaOH(aq) is mixed w/ 20.00 mL of 0.400 M HClO4(aq), the result solution would be:
So apparently the correct
4 answers
492 views
What would the pH of the solution be if the salt NaHX is dissolved in water? What anion predominates at the first equivalence
1 answer
516 views
a) If 2.40 g NaHCO3 is added to 150 mL of 0.200 M HCl, calculate the molarity of H+ after the reaction above goes to completion.
7 answers
598 views
When one half teaspoon of baking soda is dissolved in your stomach, what volume of carbon dioxide gas would be produced at body
7 answers
835 views
Determine the equilibrium constant for a 0.10M phenol (HC6H5O) solution that has a pH of 5.43 at 25 degrees C. What is the
2 answers
769 views
If 0.314g sample of a solid monoprotic acid were dissolved in water and titrated to an end point that required 44.2 mL of 0.115M
1 answer
958 views
How many Ml of 0.200 M NaOH are needed to neutralize 15.00 mL of the 0.100 M hypothetical acid H2A?
1 answer
604 views
An antacid tablet contains the weak base Mg(OH)2. After crushing the tablet and adding 20.00 mL of 1.00 M HCl(aq) to it, the
8 answers
941 views
Hydrogen iodide decomposes according to the following equation:
H2(g) + I2(g) ⇌ 2HI(g) A 2.50 L equilibrium mixture contains
1 answer
735 views
Answers (30)
so a vs t will be a straight line through the x axis? what about v vs t? in x vs t, is it a positive or negative slope?
does that mean it will just be a graph on an x-y plane??
Yes.
How can I start?
Using the half-reaction method, write a balanced chemical equation for the electrochemical cell
okay what about the others?
Ksp=produts molarity/reatants molarity
how can i find the activity coefficients?
is the concentration from the ionic strength value or from the molarity of ions?
How about the activities, how do I solve those?
Actually, i'm kind of second guessing your post. It doesn't look right to me. I just can't point my finger at it....
Whatttt? Thanks!
Nevermind I got it
i didnt mean to post that ^ twice....
What do you mean by reaching the first equilibrium point? Can I just plug the number I get by subtracting 4.07 from 14 into the HH equation?
0.00250 mol H2NCH2CH2NH2 0.001875 mol HCl =0.000625 mol H2NCH2CH2 excess now what? What do I plug into the HH equation?
Thank you, I still have a few more parts related to this specific problem. Do you want me to add onto this forum or start a new question for each part?
i'm still confused though. Wouldn't you multiply L of ethylenediamine by its M before plugging that into the ICE table?
Okay, so I got a pH of 11.7, is that correct?
So that means it would be neutral only if there was an equal amount of both NaOH and HClO4, correct?
i dont understand where to start though
nevermind, i got it. now the second part, how do i start?
what is the total volume that i should use. which value given?
Ok Thanks!
Okay, now I understand. So is my answer's correct?
This is what I got: 20.00 mL / 1000 mL * 1.00 mol = 0.0200 mol HCl (initially added) 29.50 mL / 1000 mL * 0.495 mol + 0.0146 mol NaOH (used) 0.0200 mol HCl - 0.0146 mol NaOH = 0.0054 mol HCl (used) 0.0054 mol HCl / 2 mol HCl * 58.33 g * 1000 mg = 160 mg
Why are we dividing mols HCl by 2?
Isn't there supposed to be an equilibrium arrow in the chemical equation?
It will only have one significant figure. Therefore it will be 60
Your answer will contain 1 significant figures. That will be 0.3
