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If 0.314g sample of a solid monoprotic acid were dissolved in water and titrated to an end point that required 44.2 mL of 0.115M NaOH, what is the molecular mass of the unknown acid?
7 years ago

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DrBob222
HA + NaOH ==> NaA + H2O
mols NaOH = M x L = ?
1 mol HA = 1 mol NaOH; therefore, mols HA = mols NaOH.
Then mol = g/molar mass. You know mpols and grams, solve for molar mass.
7 years ago

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