Asked by sea lively
Consider the titration of 10.00 mL of a 0.250 M aqueous solution of ethylenediamine (H2NCH2CH2NH2) with 0.250 M HCl(aq). pKb1 = 4.07 and pKb2 = 7.15.
What is the pH of the ethylenediamine solution prior to the start of the titration?
What is the pH of the ethylenediamine solution prior to the start of the titration?
Answers
Answered by
DrBob222
If we let BH stand for ethylenediamine, it has two basic components; however, only the first one needs to be considered.
pKb = -log Kb. You know pKb, convert to Kb. Then
...............BH + HOH ==> BH^+ + OH^-
I............0.25......................0...........0
C.............-x........................x............x
E,,,,,,,,,,,,,,0.25-x................x.............x
Write the Kb expression, plug in the E line and solve for x = PH^-. Convert to pH.
pKb = -log Kb. You know pKb, convert to Kb. Then
...............BH + HOH ==> BH^+ + OH^-
I............0.25......................0...........0
C.............-x........................x............x
E,,,,,,,,,,,,,,0.25-x................x.............x
Write the Kb expression, plug in the E line and solve for x = PH^-. Convert to pH.
Answered by
sea lively
Okay, so I got a pH of 11.7, is that correct?
Answered by
sea lively
i'm still confused though. Wouldn't you multiply L of ethylenediamine by its M before plugging that into the ICE table?
Answered by
DrBob222
It's late and I'll calculate it tomorrow and see if I get that answer. The volume doesn't matter. The concentration is what you want. It's 0.25 M whether it's 1 mL or 1000 mL.
Answered by
DrBob222
Yes, 11.7 is correct.
Answered by
sea lively
Thank you, I still have a few more parts related to this specific problem. Do you want me to add onto this forum or start a new question for each part?