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Asked by Sue

Let’s say you do a titration of the acid and realize it took you 14.29mL of 0.103 mol/L NaOH(aq) to neutralize all the acid. How many moles of base did it take?
12 years ago

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Answered by DrBob222
mols = M x L = ?
12 years ago
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Let’s say you do a titration of the acid and realize it took you 14.29mL of 0.103 mol/L NaOH(aq) to neutralize all the acid. How many moles of base did it take?

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