mahesh
This page lists questions and answers that were posted by visitors named mahesh.
Questions
The following questions were asked by visitors named mahesh.
. A boat is travelling on a bearing of 25° east of north at a speed of 5 knots (a knot is 1.852 km/h). After travelling for 3 hours, the boat heading is changed to 180° and it travels for a further 2 hours at 5 knots. What is the boat’s bearing from its o...
13 years ago
Find max and min values of y=sinx sin2x
12 years ago
A 40 kg slab rests on a friction less floor.a 10 kg block rests on top of the slab.the coefficient kinetic friction between the block and the slab is 0.40.a horizontal force of 100N is applied on the 10 kg block.find the resulting acceleration of the slab...
11 years ago
A man spend 1/3 of his income on food, of the rest 1/4 on bills and 1/5 on miscellaneous things. Finally he left with Rs.1760. Find his income? a)4200 b)4600 c)4800) d)5200
10 years ago
Maths If one third of the bucket can be filled in 3 min,how many min it take to fill whole bucket
9 years ago
Find the orthogonal trajectories of family of the circle x2+y2=a2 where a is a parameter
9 years ago
which of the following fraction is greater than 3/4 and less than 5/6. 1/2 , 2/3 ,4/5 , 9/10.
8 years ago
the value of K+L/K-L , if K/L = 7 ?
8 years ago
a train of length 100m runs at a speed of 120km/hr from north to south. another train of length 150m travels with a speed of 80 km/hr from south to north. what is the time required to cross each other ?
8 years ago
Answers
The following answers were posted by visitors named mahesh.
what happend 2 ur mobile? i was trying 2 call u but i got this msg: welcome 2 D jungle network,D monkey u r tring 2 call is on tree plz try later.
17 years ago
Weight is mass m times acceleration due to gravity g, which is given by g=GMm/R^2 where M and R are mass & radius of Earth and G is Universal Gravitational Constant. For new planet, g`=G(0.1Mm/(R/2)^2 =0.1GMm/R^2/4 =GMm(0.1x4)/R^2=0.4GMm/R^2 Hence g/g`=0....
12 years ago
Square has all sides equal hence 2x-5=x+8 or 2x-x=8+5 (by subtracting x and adding 5 on both sides) Thus x=13 inches. Check: 2x13-5=8+13 or 26-5=21.
12 years ago
t^2=2x3.14x0.47/a Or, a=6.28x0.47/1.43^2=0.43 m/sec^2
12 years ago
Heat released by 0.5 kg silver=heat gained by 1 kg water upto final temp T. Or 0.5(2.4x100)(150-T)=1(4.18x1000)(T-5) Or 1.2(150-T)=41.8(T-5) Or 180-1.2T=41.8T-209 Or 43T=389 Or T=9.05 deg Celsius
12 years ago
Components of a force P due North-West acting at an angle A from North will be PcosA and PsinA in North and West directions respectively and should be equal in magnitude to the force acting on the object. Thus PcosA=83.4 and PsinA=47.2. Therefore tanA=47....
12 years ago
Please see your third line: It should be 4y-3y=20-5 or y=15, by subtracting first equation from second. Now x+3*15=5 Or x=5-45=-40. Check:-40+4*15=20 by putting values in second equation. This -40=15-60=-40 OK.
12 years ago
v=u+at or 220/4=200/2+a*1 55=50+a or a=5m/s^2 Again, v=55+5*1=60m/sec at the start of 7th second.
12 years ago
Let the integers be x and x/4.Then x/4+12=x-3 or x+48=4x-12 by multiplying both sides by 4. Or -3x=-20-48 or x=20 which is the larger integer. Smaller one is then 20/4=5. Check:5+12=17=20-3 OK.
12 years ago
Let present age of Kristen be x and of Daniel be y.Then after 1 year, x+1=4(y+1)or x-4y=3.....Eq.1 After 10 yrs from then, ages will be (x+1)+10=2[(y+1)+10] Or x+11=2y+22 Or x-2y=11 .....Eq.2. Subtract eq. 1 from eq.2 and solve. We get y=4 and x=19. Check...
12 years ago
Yes please. 10 cubed is 1000 and cuberoot of q^36=q^(36/3)=q^12
12 years ago
Let it be x yrs ago, when Lisa was 15-x and her father was 40-x. Then- 40-x=6(15-x) or 40-x=90-6x Or 6x-x=90-40 or 5x=50 thus x=5. Let Bob be x yrs and Joel be 3x. Then (x+7)+(3x+7)=58 or 4x+14=85 Or 4x=44 hence x=11. Thus Bob is 11 and Joel is 33. After...
12 years ago
v=u+ft or 30=10+2t t=(30-20)/2=10 secs.
12 years ago
If one train has a velocity of V km/h, the other one will have velocity V+5 km/h approaching the first train. Therefore Relative velocity will be V+V+5=2V+5 km/h. Distance travelled by them in 2 hrs is 340-30=310km which is =2(2V+5) Thus 4V+10=310 or 4V=3...
12 years ago
Lemon juice=x Oil=2x x+2x=3x=36
12 years ago
9.95x+11.5y=305.05 x+y=29 9.95x+9.95y=29*9.95 Or (11.50-9.95)y=305.05-288.55 1.55y=16.5 y=16.5/1.55=10.6, say 11 yellow shirts 29-11=18 white shirts 11*11.5+18*9.95=305.6 OK.
12 years ago
If the number is x, then 3x-8 is=or greater than 2x. Agnus has x bones and Ignatz has x+5. Then x+x+5=27 or 2x=27-5=22 Or x=11. Ignatz has 11+5=16. Kathy mis x and John is x+10 Then x+x+10 is greater than 60 Or 2x+10is greater than 60 Or 2x 10 is greater...
12 years ago
PS: There is slight typo. Please readt first line as 'Kath is' and third line as 2x+10.
12 years ago
If cos^-1x=A then cosA=x and if (cosx)^-1=A then A=1/cosx
12 years ago
If house costs x and lot costs y then x+y=86000, and x=6y+2000 or x-6y=2000. Subtracting second eq. from first we get 6y+y=86000-2000 or 7y=84000 or y=12000. Thus lot costs $12000 House costs 86000-12000=$74000.
12 years ago
No. of $5=bills a, $10 bill=b and $20 bill=c Then a+b+c=35 5a+10b+20c=370, and b+c=a+7. Substituting value of b+c in first eq., a+(a+7)=35 or 2a=28 or a=14 and b+c=35-14=21. Substituting value of a in second eq., 14x5+10b+20c=370 or 10b+20c=370-70 Or 10b+...
12 years ago
v=u-gt or 0=15-9.81t since final velocity is 0 and ball is going against gravity. Thus t=1.53 sec. s=ut-.5gt^2=15-.5x9.81x(1.53)^2 s=22.95-11.48=121.47 which is the height the ball will go. From there it falls freely for a height of 11.47+1=12.47 ft. s=0x...
12 years ago
PS: s=11.47 which has appeared as 121.47 at one place in 4th line.
12 years ago
Force is inversely proportional to square of distance between bodies, hence F/3.75x10^-5=18^2/52^2 F=(18^2x3.75x10^-5)/52^2 =0.46x10^-5 dynes
12 years ago
-216x^3+1=1^3-(6x)^3 =(1-x)^3-3x(1-x)
12 years ago
Time for going upwqards=7/2=3.5 hrs Time for coming back=7/3.5=2 hrs Total 3.5+2=5.5 i.e. 5 1/2 hrs
12 years ago
In 1.75 hrs it fills 100% In 1 hr it will fill 100/1.75=57.14%
12 years ago
(-16)^-2/3=- 1/(16)^2/3=-1/(16^2)^1/3 =-1/256^1/3=-1/6.35=-0.157
12 years ago
(300)^1/2 /6^1/2=(300/6)^1/2 =50^1/2=7.07
12 years ago
24x^2+42x+15=3(8x^2+14+5) =3(8x^2+10x+4x+5) 3[2x(4x+5)+1(4x+5)] =3(4x+5)(2x+1)
12 years ago
Please read second expression as 3(8x^2+14x+5)
12 years ago
Total money=x. Spent in I store=(x/2)+20 Remaining amt=x-[(x/2)+20]=(x/2)-20 Spent in II store=1/2[(x/2)-20]+20 =(x/4)+10 Total expenditure is x x=(x/2)+20+(x/4)+10 Or x=(3x/4)+30 Or x-3x/4=30 x/4=30 or x=120. Check: Spent in I store =60+20=80. Remaining=...
12 years ago
Relative velocity=45+55=100mph Time taken to cover the total distance=150/100=1.5 hr i.e. 1hr 30min Meeting time is 2:15+1:30=3:45pm
12 years ago
Distance covered in 4 hrs=4y Return distance=2x4y=8y and speed=5y Hence time of return trip=8y/5y=1.6hr Halt=1hr Total time=4+1+1.6=6.6hrs
12 years ago
1hr10min=1+10/60=1+1/6=7/6hr Distance=48x7/6=56miles
12 years ago
Sorry. I wanted it to be (1-6x)^3-3x6x(1-6x)
12 years ago
1. B. 3/7 = 3*6/7*6 = 18/42. 2. D.18/30 = 6/10 = 6*10/10*10 =60/100
8 years ago