Question

Force of attraction between two spheres is 3.75 x 10?-5 dyne when the spheres are placed 18 cm apart. What is force of attraction when placed 52 cm apartÉ

Answer 1

Force is inversely proportional to square of distance between bodies, hence F/3.75x10^-5=18^2/52^2
F=(18^2x3.75x10^-5)/52^2
=0.46x10^-5 dynes