Asked by Lynda
Force of attraction between two spheres is 3.75 x 10?-5 dyne when the spheres are placed 18 cm apart. What is force of attraction when placed 52 cm apartÉ
Answers
Answered by
mahesh
Force is inversely proportional to square of distance between bodies, hence F/3.75x10^-5=18^2/52^2
F=(18^2x3.75x10^-5)/52^2
=0.46x10^-5 dynes
F=(18^2x3.75x10^-5)/52^2
=0.46x10^-5 dynes
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