Asked by tobby
                A 500 g piece of silver at 150 degree Celsius is submerged in 1000 g of water at 5 degree Celsius to be cooled. determine the final temperature of silver and water given
 
Cwater = 4.18 x 10 ^3 J/kg degree Celsius
Csilver = 2.4 x 10^2 J/kg degree Celsius
            
        Cwater = 4.18 x 10 ^3 J/kg degree Celsius
Csilver = 2.4 x 10^2 J/kg degree Celsius
Answers
                    Answered by
            mahesh
            
    Heat released by 0.5 kg silver=heat gained by 1 kg water upto final temp T.
Or 0.5(2.4x100)(150-T)=1(4.18x1000)(T-5)
Or 1.2(150-T)=41.8(T-5)
Or 180-1.2T=41.8T-209
Or 43T=389
Or T=9.05 deg Celsius
    
Or 0.5(2.4x100)(150-T)=1(4.18x1000)(T-5)
Or 1.2(150-T)=41.8(T-5)
Or 180-1.2T=41.8T-209
Or 43T=389
Or T=9.05 deg Celsius
                    Answered by
            IT IS RIGHT STOP 
            
    HATING IT IS RIGHT STUPIDS
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.