Asked by anemone
a piece of silver metal is taken from a furnace where the temperature is 75C and placed on large block of ice T 0.0C. assuming that all heat is given up by the silver is used to melt the ice,how much ice is melted?
Answers
Answered by
Damon
Csilver * mass of silver * 75 = mass of ice * heat of fusion of water
Answered by
Kent
Summation of Q = 0
Qsilver + Qice = 0
Qsilver = (mass of silver)(Csilver)(final temp - initial temp)
Use Latent heat because ice transformed phase to water
Qice = (mass of ice)(heat fusion of water)
mass of silver * Csilver * (0-75) + mass of ice * heat fusion of water
Isolate and you'll get:
mass of ice * heat fusion of water = Csilver * mass of silver * 75
mass of ice = (Csilver * mass of silver * 75)/heat fusion of water
Qsilver + Qice = 0
Qsilver = (mass of silver)(Csilver)(final temp - initial temp)
Use Latent heat because ice transformed phase to water
Qice = (mass of ice)(heat fusion of water)
mass of silver * Csilver * (0-75) + mass of ice * heat fusion of water
Isolate and you'll get:
mass of ice * heat fusion of water = Csilver * mass of silver * 75
mass of ice = (Csilver * mass of silver * 75)/heat fusion of water
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