bun
This page lists questions and answers that were posted by visitors named bun.
Questions
The following questions were asked by visitors named bun.
the shortest and longest wavelength series in singly ionized helium is 22.8nm and 30.4nm . Are they right? How many orders we can see between the angles range observations 30 and 90 in the Balmer's series?
15 years ago
Thank you drwls, My problem is a. The lifetime of the levels in a hydrogen atom are of the order 10-E8s. What is the evergy uncertainty of these states? Compare this result with the energy value of the first excited state. b. Find the shortest and the lon...
15 years ago
What is the minimum lens size (in meters) that will permit just resolving 2 stars 1.1 second apart using light of 510nm?
15 years ago
6.2(+_ 0.2) - 4.1 (+_ 0.1 ) + ? [6.2( +_ 0.2) - 4.1(+_ 0.1)] : 9.43(+_0.05) find absolut uncertainty and relative uncertainty. PLEASE HELP:I solved them and got the exact absolute uncertainty like the answer key, but I didn't get right answer of relative...
15 years ago
Species of arsenic found in kriking water include (AsO3)3-, (CH3)2(AsO2)2-, (CH3)AsO3 2-, and (AsO4)3-. Pure water containing no arsenic was spiked with 0.40microgram arsenate/L. Seven replicate determinations gave 0.39, 0.40, 0.38, 0.41, 0.36, 0.35 and 0...
15 years ago
how many milliter of .246 M HNO3 should be added to 213 ml of 0.00666 M 2,2'-bipyridine to give a pH of 4.19? please help, does this problem need to be solved with ka or kb?. Is 2,2'- bipyridine a base, this is the problem from my text book, but it is not...
15 years ago
Please tell me where I can find the articles ( free) to represent the Setvens rearrangement and Favorskii rearrangement. I have to have them for presentation but I have not taughed about these reaarangenment yet. I hope somebody on Jiskha will help me to...
14 years ago
the aprroximate method to solve the shrodringer equation for hydrogen like atom? Please help, thank
14 years ago
South Africa gained its independence from Britain in 1910. Why did this not lead to freedom and equality in South Africa What was that policy called!?
3 years ago
x^2 - 3x -20
3 years ago
Answers
The following answers were posted by visitors named bun.
Is D~11.7*10^-2
15 years ago
i solved D~11.7*10^-2, but the answer key is .0956
15 years ago
increasing atomic radius: oxygen<carbon<aluminum<potasium
15 years ago
neon<oxygen<sulfur<aluminum
15 years ago
ionization energy is the minimum energy (Kj/mol)required to remove an wlectron from a gaseous atom in its ground state. affinity energy: the negative of the energy change that occurs when an electron is accepted by an atom in the gaseous state to form an...
15 years ago
Electronegativity of fluorine is the highest among the chemical element(its electronegativity = 4),so F tends to receive electron, not yield. Therefore, fluorine has the higher ionization energy than iodine.
15 years ago
the properties of elements are based on the valence electron, the elements in the same family generally have similar properties because they have the same number of valence electron.
15 years ago
They are correct b) (1.2,0) and(0,20
15 years ago
deltaG = -RTlnK R=8.314J/mol.K you got R, T so K found by that formula.
15 years ago
let y=0, --> x= 6/5=1.2 let x=0 --> y = 6/3 = 2
15 years ago
as t-->0, we have 8t-->0, so lim (sin(8t))^2/t^2 = [lim sin(8t)/t].[limsin(8t)/t] as8t-->0 =8.[limsin(8t)/8t].8[limsin(8t)/8t], 8t-->0 = 8*1*8*1= 64 you know the formula lim (sint/t)=1 as t-->1, aren't you?
15 years ago
y' = (3-secx)'tanx -(3-secx)(tanx)'/(tanx)^2 = -secx(tanx)^2 - (3-secx)secx/(tanx)^2 = -secx[(tanx)^2 + (3-secx)]/tan^2x =-[(tan)^2 +3 -secx]/sinx
15 years ago
4.6*10^-3 = [NO2]^2/[N2O4] => [NO2] =3.48*10^-1
15 years ago
MnO4- +5e -> Mn2+}*2 C+1 -2e -> C+3 }*5 2MnO4- + 5C6H7O +6H+ -> 2Mn2+ + 5C6H7O2 + 3H2O Step 1: realize the oxidation of element: (oxidation of H and O not change) write half reaction equalize the number of election yieled and accepted by the coefficient (...
15 years ago
mol Na2S = (0.01mol/L)*2.00ml*1L/1000mL = 0.002mol mol Hg(NO3)2 = 50.0ml*(0.0005mol/L)*1L/1000mL = 0.000025=2.5*10^-5 Hg(NO3)2 limiting reagent max mass of precipitate = 2.5*10^-5 * molar mass of Hg(NO3)2
15 years ago
babyface is correct :) i got 100
4 years ago