Asked by Zoey

find the derivative of

y= 3-secx/tanx

15 years ago

Answered by bun

y' = (3-secx)'tanx -(3-secx)(tanx)'/(tanx)^2

= -secx(tanx)^2 - (3-secx)secx/(tanx)^2

= -secx[(tanx)^2 + (3-secx)]/tan^2x

=-[(tan)^2 +3 -secx]/sinx

15 years ago

Answered by joans

Y=-cosxln(secx+tanx)

13 years ago

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