find the derivative of

Question

y= 3-secx/tanx

Answer 1

y' = (3-secx)'tanx -(3-secx)(tanx)'/(tanx)^2

= -secx(tanx)^2 - (3-secx)secx/(tanx)^2

= -secx[(tanx)^2 + (3-secx)]/tan^2x

=-[(tan)^2 +3 -secx]/sinx

Answer 2

Y=-cosxln(secx+tanx)