Asked by bun
how many milliter of .246 M HNO3 should be added to 213 ml of 0.00666 M 2,2'-bipyridine to give a pH of 4.19?
please help, does this problem need to be solved with ka or kb?. Is 2,2'- bipyridine a base, this is the problem from my text book, but it is not given by the formula, I can not find the formula in my text book and ka or kb as well. I hope to be helped soving it. Thanks a lot.
please help, does this problem need to be solved with ka or kb?. Is 2,2'- bipyridine a base, this is the problem from my text book, but it is not given by the formula, I can not find the formula in my text book and ka or kb as well. I hope to be helped soving it. Thanks a lot.
Answers
Answered by
DrBob222
Yes, 2,2'-bipyridine is a base. Here is a site that shows the formula.
http://en.wikipedia.org/wiki/2,2%27-Bipyridine
It can react with 2HNO3 to form a salt. I think you want to use the Henderson-Hasselbalch equation.
pH = pKa + log (base/acid). You will want to add enough HNO3 to form the corresponding salt (the conjugate acid) but have enough of the unreacted base left over to provide the buffer you need. Start by plugging in pH and pKa and solving for base/acid ratio.
http://en.wikipedia.org/wiki/2,2%27-Bipyridine
It can react with 2HNO3 to form a salt. I think you want to use the Henderson-Hasselbalch equation.
pH = pKa + log (base/acid). You will want to add enough HNO3 to form the corresponding salt (the conjugate acid) but have enough of the unreacted base left over to provide the buffer you need. Start by plugging in pH and pKa and solving for base/acid ratio.
Answered by
Chhong sreyvi
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