Steve 2.0
This page lists questions and answers that were posted by visitors named Steve 2.0.
Questions
The following questions were asked by visitors named Steve 2.0.
Answers
The following answers were posted by visitors named Steve 2.0.
well, there is always at least one real root for a cubic. Just not always rational. Since f(-6) = -24 f(-5) = 30 you know there is a root inside (-6,-5). The work comes in narrowing it down a bit more.
11 years ago
If you want the graph shifted up by 12, then you need to add 12 to all the values of f(x): g(x) = f(x)+12 = x^2+15
11 years ago
well, there are lots of methods. An easy one is bisection. Since you know the root is between -6 and -5, try -5.5 f(-5.5) = 6.625 Now you know that the root r is in (-6,-5.5), so try -5.75 f(-5.75) = -7.73 r is in (-5.75,-5.5) f(-5.625) = -0.322 each time...
11 years ago
no use for derivatives here. 90% of capacity is 7200 fish So, just solve for t when P(t) = 5000 or 7200
11 years ago
(1/2)^t/5730 = .16 t/5730 = log(.16)/log(.5) t = 5730*log(.16)/log(.5) t = 15149 makes sense. 12.5% left would be three half-lives, or 17190 years
11 years ago
degree of a polynomial is the highest power of x. in this case, 2.
11 years ago
The slant height of the cone is the original radius of the paper circle. So, r = 10 The new circumference of the base is .6 of that, so 40% of the circle was lost. 40% of 360° is 144°.
11 years ago
there is no common denominator. π is irrational! That means it cannot be expressed as a ratio of two integers.
11 years ago
looks good to me
11 years ago
yes, if you lose the space. More common would be 3A.
11 years ago
Hmmm. z - 1/5 > 1/4 z > 1/4 + 1/5 z > 9/20 You don't swap direction unless multiplying or dividing by a negative value. Addition and subtraction do not affect the sense of the inequality.
11 years ago
well, just plug in n=9 A(9) = -14 + (9-1)(2) = 2
10 years ago
correct
10 years ago
Or, you can reason that since y=kx, y/x is constant. So, 14/-4 = y/-6 y=21 And you don't even have to figure out what k is.
10 years ago
First, it's "heading" or "course," <b>not</b> "bearing." Just figure the x- and y-displacements for each leg of the trip. Add them up for a final location. Then figure the distance and (yes) <u>bearing</u> of the port from there. What do you get? I'll che...
10 years ago
The population by 4000 for 15 years, or 60,000 So, it must have been 450,000-60,000 = 390,000 in 2010 p(x) = 390 + 4x
10 years ago
64 = 4^3 so log_4(64) = 3log_4(4) = 3*1 = 3
10 years ago
If you mean |x|-15 then as usual, the graph is shifted down 15 units. It's a lot easier to figure out what you mean if you just use proper notation. If you meant |x-15| then none of the choices is correct.
10 years ago
any line y = -1/12 x + c will be parallel to that line, for any value of c that you like.
10 years ago
4s+6h = 52 2h = s+1 Now you can find both costs.
10 years ago
For x people, we have A: 50+25x B: 130+20x So, you want 50+25x = 130+20x
10 years ago
v = 2pi*r*w just watch the units: w = /min r = ft, so c=2pi*r = ft
10 years ago
figure the length of the diameter d, using your distance formula. Then the area of the circle is A = πd^2/4
10 years ago
-(13x)^0 y^-7 z anything^0 = 1, so -z/y^7
10 years ago
(-2)^-3 (-24) = 1/(-2)^3 * (-24) = -24/-8 = 3
10 years ago
x/2 + 1 < 5/2 x/2 < 3/2 x < 3
10 years ago
t <= 9
10 years ago
∫te^at dt needs to be done with integration by parts, with u = t, du = dt dv = e^at dt, v = 1/a e^at Do all that and you have ∫0.02te^(-0.05t) dt = -(0.4t+8)e^(-0.05t) now just plug in the numbers
10 years ago
#1 any rational function with vertical asymptotes will do this: 1/(x-1)(x+1) #2 f(x) = x+1 for x <= 1 x-1 for x > 1 just any function where there is a finite break at some x value
10 years ago
if all you have is angles, there is no way to find the sides. All similar triangles have the same angles, but different sides. However, you do know that X/sin40 = Y/sin80 what's the stuff about a plane on top? What does that have to do with anything?
10 years ago
the radius is 60 135-60 = ?
10 years ago
well, now you know that d = p-3 - (p-5) = 2 2p-15 - (p-3) = 2, so p=14 so, a = p-5 = 9 n/2 (2*9 + (n-1)*2) = 180 n = 10
10 years ago
recall the chain rule fy/fx = dy/du du/dx #1: u=3x^3 dy/dx = -sin(u) (9x^2) = -9x^2 sin(3x^3) #2: u = x^4 + e^2x) dy/dx = 1/u du/dx = (4x^3 + 2e^2x)/ln(x^4+e^2x)
10 years ago
oops #2 is (4x^3 + 2e^2x)/(x^4+e^2x)
10 years ago
and it is correct or, as we usually write it, 1.25x10^-4 or 1.25 * 10^-4
10 years ago
well, what is (20x)^2 - pi(4x)^2 ?
10 years ago
since time = distance/speed, Mrs Healthy took 800m/(2400 m/hr) = 1/3 hr = 20 min So, Mrs Wise's speed = 800m/16min = 50m/min = 3000m/hr
10 years ago
6d^4+9d^3-12d^2 first, factor out the d^2 d^2(6d^2+9d-12) Now, how about a 3? 3d^2(2d^2+3d-6) Now, note that the discriminant is 57, so the roots will contain √57. No rational roots exist. Can't factor it any further using integers.
10 years ago
you are correct
10 years ago
right on
10 years ago
nope. There are exactly as many roots as the degree of the polynomial. In this case, 2, since the highest power is x^2. There are three terms, but only two solutions. Recall your quadratic formula. It only produces two values.
10 years ago
since the period is proportional to r^(3/2), replacing r with (9r) produces a period 9^(3/2) = 27 times longer.
10 years ago
me too.
10 years ago
42
10 years ago
max distance is when θ=45° so, use that to figure x- and y-components of initial velocity,
10 years ago
right on
10 years ago
pick one of the acute angles. Call it t. Label the opposite side x, and the hypotenuse h. Then sin(t) = x/h Do the same for the other angle and side, or use the Pythagorean Theorem to find the other side.
10 years ago
well, sin x = 12/37 cos x = 35/37 so, x is close to zero either (b) or (c) push the buttons and find out
10 years ago
tan 29.3° = 9/16, so width = diagonal * sin 29.3° length = diagonal * cos 29.3°
10 years ago
linear pairs add to 180, so (assuming the usual typos) x-30 + x+76 = 180 x = 77 Now you can figure the two angles.
10 years ago
since LMO+NMO = LMN, x+34 + NMO = 6x-28 But, MO bisects LMN, so LMO=NMO x+34 + x+34 = 6x-28 2x+68 = 6x-28 4x = 96 x = 24 Now you can figure the actual degree measures.
10 years ago
Good catch.
10 years ago
well, the distance between those points is the radius of the circle.
10 years ago
you can find the radius: it's the distance between the points.
10 years ago
f◦g = √(g-1) = √(x^2-1) You know that √n has domain n>=0. SO, you need (x^2-1) >= 0. g◦f = f^2 = (√(x-1))^2 = x-1 I'm pretty sure you can handle that one, right?
9 years ago
Find the lowest common denominator. The just sort the numerators. For example, 5/8,11/12,7/4,9/16 = 30/48, 44/48, 84/48, 27/48 Now you just have to sort 30,44,84,27 do the others in like wise.
9 years ago
AcTuAlLy if you BoThEreD to do WERK (sis) then you might know der!v@t!ve$
6 years ago
Yo I think that answer was wrong :skull:
2 years ago