Asked by Jayesh

A satellite in orbit around the earth has a period of one hour. An identical satellite is placed in an orbit having a radius that is nine times larger than that of the first satellite. What is the
period of the second satellite?

Answers

Answered by Steve 2.0
since the period is proportional to r^(3/2), replacing r with (9r) produces a period 9^(3/2) = 27 times longer.
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