F = G Mm/r^2
g = F/m = G M/r^2
g at R = Re = G M/Re^2
g at R = Rsat = G M/Rsat^2
g at Rsat/g at Re = G M/Rsat^2/GM/Re^2
= Re^2/Rsat^2
= 6370^2/6470^2
for percent multiply by 100
A satellite is placed in orbit 100 km above the surface of the earth (radius = 6370 km, mass = 5.98 x 1024 kg).
What is the value of the acceleration of gravity at that altitude as a percentage of the acceleration at the surface of the earth?
1 answer
52 answers