Which method is the best method for solving the equation

right on

thank you

I agree. Unless the coeffiecients are relatively small, I usually don't waste too much time trying to factor it.

If the x^2 term has a coefficient of 1, and the x term is even I ALWAYS complete the square, it is much faster than the formula. Otherwise,
I do a quick calculation of √(b^2 - 4ac)
If I get a whole number, I know it would have factored, but I am almost done anyway, so I finish with the formula.

for this one:
x = (123 ± √15033)/16

I think he means 13x, not 123x.

Practice Answers:

B
C
A
A
C
D
C
A
Unit 4 Lesson 6 Georgia Lessons
100%

for practice:

1. B
2. C
3. D
4. A
5. D
6. D
7. C
8. A

Anonymous is right not Skidaddle Skidoodle.

fortnite

The best method for solving a quadratic equation depends on the specific equation and its factors. In the given equation, 8x^2-123x+3=0, using the quadratic formula would be the most effective method. The quadratic formula allows you to find the solutions of a quadratic equation of the form ax^2 + bx + c = 0, where a, b, and c are constants.

To use the quadratic formula, you need to identify the values of a, b, and c from the given equation. In this case, a = 8, b = -123, and c = 3. The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

By substituting the values of a, b, and c, you can calculate the solutions for x. The plus-minus symbol (±) indicates that you need to calculate both the positive and negative solutions.

However, if the equation is easily factorable, factoring would be a simpler method. In some cases, graphing can also be helpful to visualize the equation and estimate the solutions. Square roots are usually not applicable for solving quadratic equations directly, as they are more useful in solving simple equations involving a single variable.