Steve - ouch!

This page lists questions and answers that were posted by visitors named Steve - ouch!.

Questions

The following questions were asked by visitors named Steve - ouch!.

Answers

The following answers were posted by visitors named Steve - ouch!.

scott got it right. My bad.

1/0.342 = 2.924 √0.0625 = 0.25

1=1^2 assume true for n=k: 1+3+...+(2k-1) = k^2 Now check for n=k+1: 1+3+...+(2k-1)+(2k+1) = k^2+(2k+1) = (k+1)^2 So, P(k) => P(k+1) P(1), so P(all k)

Good call. I forgot the 4t But 450/e^8 = 0.15 The answer is still big, though.

Sorry - I missed the "three"

Ouch - my BAAADDDD!

Your triangle has y=2 r=√229 so, x=15 Now, all you need to remember is that sinθ = y/r cosθ = x/r tanθ = y/x Now just plug and chug, remembering your double-angle identities.

I meant (- ∞, 2) If we call the two intervals A and B, then my first post was B-A, not A∩B

that would of course be s = rθ = 8.4 * 105(π/180)

oops. that is the minor arc. Change 105 to (360-105)

Clearly I was not thinking clearly. As usual, Scott is correct.

If it takes them x hours working together, then 1/2 + 1/3 = 1/x The equation reflects the idea of how much of the job each can do in an hour. Add that up, and it shows how much of the whole job gets done in an hour.

Actually, the above solution is wrong. The total is not 20. I need to think on it some more.

nice catch. I originally included the 1/2, but then I noticed that the widths were not all the same, and in my PS I left it out. But I'm sure William picked right up on that... ... ...

Oops. confused y̅ with the moments from the y-axis. y̅ = 5/4 ∫ 1/2 y^2 dx = ∫[0,ln5] 1/2 e<sup>-2x</sup> dx