Asked by Reece
Given dy/dt=4y and y(2)=450. Find y(8).
Answers
Answered by
Steve
dy/dt = 4y
dy/y = 4 dt
lny = 4t+ln(c)
y = c*e^(4t)
y(2)=450, so
c*e^2 = 450
c = 450/e^2 ≈ 60.9
y = 60.9 e^(4t)
so, now find y(8)
dy/y = 4 dt
lny = 4t+ln(c)
y = c*e^(4t)
y(2)=450, so
c*e^2 = 450
c = 450/e^2 ≈ 60.9
y = 60.9 e^(4t)
so, now find y(8)
Answered by
Reece
I keep getting some huge number when I do 60.9(e^(4*8)) and I know that's not right..
Answered by
bobpursley
Let me recheck Steves response
lny = 4t+ln(c)
y = ke^4t
y(2)=450, so
c*e^8 = 450 Here is where I change to my work.
c = 450/e^8 ≈ 2981
y = 2981 e^(4t)
y(8)=2981e^16=2.64e10
lny = 4t+ln(c)
y = ke^4t
y(2)=450, so
c*e^8 = 450 Here is where I change to my work.
c = 450/e^8 ≈ 2981
y = 2981 e^(4t)
y(8)=2981e^16=2.64e10
Answered by
Steve - ouch!
Good call. I forgot the 4t
But 450/e^8 = 0.15
The answer is still big, though.
But 450/e^8 = 0.15
The answer is still big, though.
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