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Sanz
Questions (11)
A sample of (N2H5)2C3H4O4 contains 1.084 x 1024 carbon atoms. How many moles of hydrogen atoms are there in the same sample?
2 answers
3,057 views
A car is traveling along a road, and its engine is turning over with an angular velocity of +190 rad/s. The driver steps on the
1 answer
664 views
A 0.0124-kg bullet is fired straight up at a falling wooden block that has a mass of 3.96 kg. The bullet has a speed of 756 m/s
3 answers
1,384 views
A 0.0124-kg bullet is fired straight up at a falling wooden block that has a mass of 3.96 kg. The bullet has a speed of 756 m/s
0 answers
1,367 views
A 0.0124-kg bullet is fired straight up at a falling wooden block that has a mass of 3.96 kg. The bullet has a speed of 756 m/s
2 answers
944 views
In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push
1 answer
3,923 views
A golf ball strikes a hard, smooth floor at an angle of 33.1 ° and, as the drawing shows, rebounds at the same angle. The mass
3 answers
929 views
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees
7 answers
657 views
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees
1 answer
617 views
Two horizontal forces, and , are acting on a box, but only is shown in the drawing. can point either to the right or to the
2 answers
1,378 views
A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0 s, the x components of the puck's
2 answers
1,206 views
Answers (9)
I think it's a little more in depth than a system of eqns. :(
Well the question says the block was falling for time t until the collision, so i assumed just falling time right up to when the bullet hits. What I figured so far was a) I found Vbullet by doing mzv1-m2v2 b) then i did vf= vi+at and solved for t. I could
I get why it's twice. There's a rebound. But I don't understand how to do the vertical component. Is that correct how i showed above? but multiplied by 2?
I did 59.2 sin (33.1) for a new velocity. Then multiplied by my mass for the change in momentum (impulse). I don't think that's correct.
So F = 2141 in b. 2141 = (65.3)(a) a = 32.787 But part c asks for force, if i figure acceleration from part b, what does that do for me? Can you work with me with the numbers please?
Oh wait. Is it (v)x(t) = a and then (a)x(m) = F?
So the downward force is mg s0 (63.5)(9.81) and is my ground force the F value from b? I subtract those two and then solve for acceleration and then F? I'm not sure which are the downward and ground forces..?
Need help with only part b. Got the rest
I figured it out, but thank you!
