Sanz

A sample of (N2H5)2C3H4O4 contains 1.084 x 1024 carbon atoms. How many moles of hydrogen atoms are there in the same sample? Avogadro’s number = 6.022 x 1023.

I figured it out, but thank you!

Need help with only part b. Got the rest

So the downward force is mg s0 (63.5)(9.81) and is my ground force the F value from b? I subtract those two and then solve for acceleration and then F? I'm not sure which are the downward and ground forces..?

Oh wait. Is it (v)x(t) = a and then (a)x(m) = F?

So F = 2141 in b. 2141 = (65.3)(a) a = 32.787 But part c asks for force, if i figure acceleration from part b, what does that do for me? Can you work with me with the numbers please?

I did 59.2 sin (33.1) for a new velocity. Then multiplied by my mass for the change in momentum (impulse). I don't think that's correct.

I get why it's twice. There's a rebound. But I don't understand how to do the vertical component. Is that correct how i showed above? but multiplied by 2?

Well the question says the block was falling for time t until the collision, so i assumed just falling time right up to when the bullet hits. What I figured so far was a) I found Vbullet by doing mzv1-m2v2 b) then i did vf= vi+at and solved for t. I could...

I think it's a little more in depth than a system of eqns. :(