A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0 s, the x components of the puck's initial velocity and acceleration are v0x = +7.2 m/s and ax = +4.3 m/s2. The y components of the puck's initial velocity and acceleration are v0y = +8.9 m/s and ay = -5.4 m/s2. Find (a) the magnitude v and (b) the direction θ of the puck's velocity at a time of t = 0.50 s. Specify the direction relative to the +x axis.

asked by Sanz

10 years ago

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2 answers

vx(t)=vxi+ax*t
=7.2 + 4.3*.5
do the same for vy(t)

then theta=arctan(vy/vx)

magnitude v= sqrt(vx^2 + vy^2)

answered by bobpursley

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I figured it out, but thank you!

answered by Sanz

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Question

A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0 s, the x components of the puck's initial velocity and acceleration are v0x = +7.2 m/s and ax = +4.3 m/s2. The y components of the puck's initial velocity and acceleration are v0y = +8.9 m/s and ay = -5.4 m/s2. Find (a) the magnitude v and (b) the direction θ of the puck's velocity at a time of t = 0.50 s. Specify the direction relative to the +x axis.

2 answers

vx(t)=vxi+ax*t
=7.2 + 4.3*.5
do the same for vy(t)

then theta=arctan(vy/vx)

magnitude v= sqrt(vx^2 + vy^2)

I figured it out, but thank you!

bobpursley · Answer

vx(t)=vxi+ax*t =7.2 + 4.3*.5 do the same for vy(t) then theta=arctan(vy/vx) magnitude v= sqrt(vx^2 + vy^2)

Sanz · Answer

I figured it out, but thank you!