Asked by frost
A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0 s, the x components of the puck's initial velocity and acceleration are v0x = +8.3 m/s and ax = +8.8 m/s2. The y components of the puck's initial velocity and acceleration are v0y = +9.6 m/s and ay = -6.1 m/s2. Find (a) the magnitude v and (b) the direction è of the puck's velocity at a time of t = 0.50 s. Specify the direction relative to the +x axis.
Answers
Answered by
Henry
V = Vo + at.
V(hor) = 8.3 + 8.8*0.5 = 12.7m/s.
V(ver) = 9.6 + (-6.1)*0.5 = 6.55m/s.
a. V^2 = (12.7)^2 + (6.55)^2 = 204.19,
V = sqrt(204.19) = 14.3m/s = Magnitude.
b. tanA = Y/X = 6.55 / 12.7 = 0.516,
A = 27.3Deg. = Direction.
V = 14.3m/s @ 27.3Deg.
V(hor) = 8.3 + 8.8*0.5 = 12.7m/s.
V(ver) = 9.6 + (-6.1)*0.5 = 6.55m/s.
a. V^2 = (12.7)^2 + (6.55)^2 = 204.19,
V = sqrt(204.19) = 14.3m/s = Magnitude.
b. tanA = Y/X = 6.55 / 12.7 = 0.516,
A = 27.3Deg. = Direction.
V = 14.3m/s @ 27.3Deg.
Answered by
alex
thanks guys for the help.
now my mom wont beat me since I've done my work
(my dad cant beat me because he went to go get milk a few years ago)
now my mom wont beat me since I've done my work
(my dad cant beat me because he went to go get milk a few years ago)
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