NB

I am stuck on the following question in chapter 1: What is ironic about the “Christ killer” label so common in Eastern Europe? (Think about the historic events of the crucifixion—hint, answer who?) And the following in chapter 2: In what ways has Rivkeh c...

Hi, Yes I have read through that site after reading the 2 chapters, as well as bookrags and no specific answers to my questions on either. Thanks

pV=nRT (bottom of ocean) pV=nRT (top of ocean) n,R,T are all constants so those cancel out pV(bottom)= pV(top) pV(bottom)/p(top)=V(top) 1.6*1.6/1.0=V V=2.56cm3

45 seconds

How much heat in Joules is needed to evaporate a cup of water (250g) at 100 degrees Celsius?

W = 189*13/27 = 91 How much money did Jason have? J = 3(91-63) = 3*28 = $84 How much money do they have altogether to start with? =84+91 = 175 How much money do they have altogether at the end? =84+(91-63) = 84+28 = 112

Solving Eq: 12/13 W = 3W - 189 3W-(12/13)W = 189 (3*13/13)W -(12/13)W = 189 (39-12/13)W = 189 => 27/13W =189

Mass of solution = 3.69g + 21.70g =25.39 g Volume of solution = 25.39g / 1.11g/mL =22.9 mL = 0.0229 L Moles KCl = 3.69 g / 74.5513g/mol = 0.0494961 mol Molarity of KCl = 0.0494961 mol / 0.0229L = 2.1614 mol/L

Mass of solution = 3.69g + 21.70g =25.39 g Volume of solution = 25.39g / 1.11g/mL =22.9 mL = 0.0229 L Moles KCl = 3.69 g / 74.5513g/mol = 0.0494961 mol Molarity of KCl = 0.0494961 mol / 0.0229L = 2.1614 mol/L

Now just do that for KBr instead of KCl i.e change the molecular weight in step 3

Now just do that for KBr instead of KCl i.e change the molecular weight in step 3

g BaCl2 = 1.38moles BaCl2 x molar mass BaCl2 (which is 208.23) =287.3574g