Question

The boiling point of water at 735mmHg is 99.073C. What mass of NaCl should be added to 3.11kg water to increase the boiling point to 100.000C. Kb for water = 0.510K kg mol-1.
delta T = Kb*molality
Solve for molality.

m = moles/kg solvent.
Solve for moles.

moles = grams/molar mass
Solve for grams.
g BaCl2 = 1.38moles BaCl2 x molar mass BaCl2 (which is 208.23)
=287.3574g

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