Asked by Gina

The boiling point of water at 735mmHg is 99.073C. What mass of NaCl should be added to 3.11kg water to increase the boiling point to 100.000C. Kb for water = 0.510K kg mol-1.
Answered by DrBob222
delta T = Kb*molality
Solve for molality.

m = moles/kg solvent.
Solve for moles.

moles = grams/molar mass
Solve for grams.
Answered by NB
g BaCl2 = 1.38moles BaCl2 x molar mass BaCl2 (which is 208.23)
=287.3574g
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