a train leaves the station at a 0.0-m marker travel;ing with a constannt velocity of 36.0m/s

Question

a) how many seconds later will the train pass the 1620.0-m marker?

could you please show me how to do this and also what the formula is?

Answer 1

The markers are panels along the track to identify the location, but also gives the train engineer an idea of the speed by measuring the time elapsed when travelling between known markers.
In this case, the difference of the markers gives the distance travelled, namely 1620-0=1620 m.
The speed is 36 m/s.
Can you figure out the time in seconds using Distance=speed * time?

Answer 2

honestly i have no idea... could you please help

Answer 3

Distance = speed * time
If John travels 100 km at 50 km/h, it takes him 100/50 = 2 hours.
So if the train travels 1620 m at 36 m/s, how long does it take to make that distance?

Answer 4

Divide the distance by the velocity to get the time.
t = d / v
1620 m / 36 m/s
cancel the meters
so what's left is 1620 / 36 s
1620 / 36 s
= 45 seconds

Therefore, it will take 45 seconds for the train to pass the 1620.0-meter marker with a constant velocity of 36 m/s.

Answer 5

45 seconds