Michael G.

Ben, 1.use grams of Mg to moles of MgO by using molar mass of Mg, then mole ratio. 2.same process as number 1 but with O2. 3.determine which element produced less moles of MgO by comparing answer to question 1 and 2; that is your limiting reagent. which p...

Kara, the conceptual plan would be to go from grams of No2 to grams of N2 by first using the molar mass to convert grams to moles of NO2. Now use the mole ratio of NO2 to N2, then use the Molar mass of N2 to get grams of N2

El, I will get you started here. You have 22% by mass of solute Z(by mass also means w/w), which means 22 g Z/100 g soln. 22 g Z/100 g soln(1 mol Z/215 g Z)x(1.1g/ml)x(1,000ml/L)=?

Nevaeh, Before you get Dr.Bob222 to weigh on in, I want to add a little about amphoteric species. Amphoteric species are those molecules that can react as both an acid and a base. The acid donates H^+, and the base receives the proton(H^+ ion). If the aci...

Mimi, These two formulas will be helpful: P = 2(a+b), where "a" is the side length, and "b" is the base. Area= (b)(h) So for perimeter, 2(4+8)= 24 in. add first then multiply. Area= 8(3) = 24 in^2

well understood

Trinity, from the pH you can determine the H3O^+ concentration by using ph=-log[H3O^+]. Then you can use Kw=KaxKb to solve for OH- concentration 10^-12.40 = 10^log[h3o^+] = 4.0x10^-13 M = [h3o^+] Now use 4.0x10^-13[OH^-] = 1.00x10^-14 = [OH^-]= 2.5X10^-2...

You have a container that needs to hold 0.0459 mol at Stp, which means at stp you will have 273K, 1 atm, and 0.08206L(atm)/mol(K). Use formula PV=nRT, and solve for V

grammatically incorrect, the use of proper words like "going to" will work. Using ride is ok in number 2, and for number 1 because they are different action verbs. 1.going to 2.going to 3.going to(ride or take will work)

or for 3 you can use: I am going to use the bike to go to the station.

Endothermic is when heat is entering or being absorbed by an object(in a process) and this will cause the surrounding temperature to decrease. Exothermic- heat is released in a process, and the surroundings will increase in temperature

theoretical yield problem. Rather than finding Limiting reagent by getting to moles, lets do one full step becuase we are asked for grams of Al2O3. 68.1 g Al/ molar mass = mol Al times mole ratio times molar mass Al2O3. Same procedure for Fe2O3. Produced...