Asked by Trinity

What is the OH- concentration of a solution whose pH is 12.40?
Answered by Michael G.
Trinity,

from the pH you can determine the H3O^+ concentration by using ph=-log[H3O^+]. Then you can use Kw=KaxKb to solve for OH- concentration

10^-12.40 = 10^log[h3o^+] =
4.0x10^-13 M = [h3o^+]

Now use 4.0x10^-13[OH^-] = 1.00x10^-14 =

[OH^-]= 2.5X10^-2 M

Answered by Trinity
thanks@ Michael
Answered by DrBob222
pH + pOH = pKw = 14.
You know pH, solve for pOH.
Then pOH = -log(OH^-)
Substitute and solve for OH. You should get a little less than 2 but that's just an estimate.
Answered by Trinity
Thanks @ DrBob222
Answered by DrBob222
I hit the wrong key. The answer should be a little less than 3.
Answered by Snowman2
If [H3O+] = 1.7 x 10–3 M, what is the pH of the solution?
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