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Kishwa
Questions (8)
The problems:
0.0513 grams of Al (Wt. 27.0) was reacted with excess HCI to produce H2 according to the following balanced
0 answers
609 views
Urgent... Someone please help!!
Can someone please check to see if I am doing these correctly, I have a test tomorrow... Thank
0 answers
1,274 views
Can someone please explain how to convert this, sadly I was absent the day we figured out how to do this in class.
(H+1) pH
5 answers
548 views
Q) Calculate the new molarity of a 35mL sample of 0.450 M CaCl2 solution that is diluted with enough water to make 250 mL of
0 answers
509 views
Can someone please check to see if I am doing this correctly. Thank you :)
Q) Calculate the new molarity of a 35mL sample of
0 answers
515 views
Can someone please tell me if I am doing this problem correctly. Thank you!
Given: 450 mL (0.450L); 0.250 M KNO Need: Mass of KNO
0 answers
663 views
What mass of KNO3 (MW=101) is needed to prepare 45omL of 0.250 M KNO3 in water?
2 answers
795 views
What is the molarity (moles per liter) of an aqueous solution that is prepared by dissolving 5.58g NaOH (MW=40) in enough water
2 answers
549 views
Answers (5)
Thank you for the response, I understand being busy, no need to be sorry. I'm glad I could figure it out with out help. :)
Disregard. I figured it out on my own.. :) But, if anyone has a problem like this I found a really nice diagram on how to calculate. Just go to google and search for "pH problem solving diagram"
Im not sure how to edit and it didn't line up right, so Im just going to write it out. I have to figure the following from the one answer. (H+1) M, pH, (OH-1)M, pOH H+1 = 2.5x10^-5 = need pH, OH-1 and pOH pH = 2.5 --> need H+1, OH-1 and pOH OH-1 =
Thank you I get: 37g/200g x 100 = 18.5%
Thank you.. I get 5.58g NaOH / 40g NaOH / 0.25L = 0.558 NaOH solution
