Can someone please tell me if I am doing this problem correctly. Thank you!
Given: 450 mL (0.450L); 0.250 M KNO
Need: Mass of KNO
Q) What mass of KNO3 (MW=101) is needed to prepare 450mL of 0.250 M KNO3 in water?
A) 0.450 L Solution x 0.250 M KNO/1 L solution x 101g KNO/1 mol KNO
= 11.4 g KNO