Q) Calculate the new molarity of a 35mL sample of 0.450 M CaCl2 solution that is diluted with enough water to make 250 mL of solution.

A) M1V1 = M2V2
M1 = 0.450
M2 = ?
V1 = 0.035 L
V2 = 0.250 L

M2 = M1 X V1/V2

0.450 X (0.035L/0.250L) = 0.063

Did I set this up correctly and is my answer right? Thank you for helping!!

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