Juliee

The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: 1. Cs(s)-Cs(g) 2. 1/2 Cl2(g)-Cl(g) 3. Cs(g) –Cs^+(g) + e^- 4. Cl(g) + e^- - Cl^-(g) 5. Cs^+(g) +Cl^-(g)-CsCl(s) Which of these steps absorb energy and which release energy?

Based on the number of atoms per unit cell and the mass of the atom, the mass of the unit cell can be calculated. The density of the unit cell and the material as a whole can be determined from the mass and the volume of the unit cell as. D= M/V The usual...

jason has $1.56 in change in his pocket . if there is a total of 19 coins, how many quarters, dimes,nickels, and pennies does he have.

The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: 1.Cs(s)-Cs(g) 2.1/2 Cl2(g)-Cl(g) 3.Cs(g) –Cs^+(g) + e^- 4.Cl(g) + e^- - Cl^-(g) 5.Cs^+(g) +Cl^-(g)-CsCl(s) Which of these steps absorb energy and which release energy?

its pm i guess we have to multipy by 10^-12 thn i don't knw abt mass d=m/v since i don't even knw the units too hw to cont