Asked by Juliee
The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:
1. Cs(s)-Cs(g)
2. 1/2 Cl2(g)-Cl(g)
3. Cs(g) –Cs^+(g) + e^-
4. Cl(g) + e^- - Cl^-(g)
5. Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?
1. Cs(s)-Cs(g)
2. 1/2 Cl2(g)-Cl(g)
3. Cs(g) –Cs^+(g) + e^-
4. Cl(g) + e^- - Cl^-(g)
5. Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?
Answers
Answered by
DrBob222
All of your question didn't post. If you are trying to cut and paste, please be advised that cut and paste doesn't work. You must type in what you want to post.