Question

The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:
1. Cs(s)-Cs(g)
2. 1/2 Cl2(g)-Cl(g)
3. Cs(g) –Cs^+(g) + e^-
4. Cl(g) + e^- - Cl^-(g)
5. Cs^+(g) +Cl^-(g)-CsCl(s)
Which of these steps absorb energy and which release energy?

Answer 1

See my response to your earlier duplicate post. You can't cut and paste.

Answer 2

The formation of CsCl from Cs(s) and Cl2(g) involves the following steps:


1.Cs(s)-Cs(g)
2.1/2 Cl2(g)-Cl(g)
3.Cs(g) –Cs^+(g) + e^-
4.Cl(g) + e^- - Cl^-(g)
5.Cs^+(g) +Cl^-(g)-CsCl(s)

Which of these steps absorb energy and which release energy?

Answer 3

See my response to <b>iuyter</b> just a few posts above.

Answer 4

Do you wonder if i say , every time i searched i got different answers that i am confused now.now i don't know what to do.i am given a home work