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Answers (4)
The answer is D.
Keq=[NH3]^2/[H2]^2[N2]. Plug in the concentrations for each and you should get 0.014. So the answer is B.
Answer B is correct.
The answer is c. Rate =k[A]. This is a graph of ln[A] vs. time and it is a straight line indicating a first order reaction. In this graph, k=slope. So you can just plug in the slope for k and solve. The answer comes out to be c. I hope this helps!
