Given the equilibrium concentrations in the table, what is the equilibrium constant for the synthesis of ammonia at this temperature?
3H2(g) + N2 <---> 2NH3(g)
[H2] - 0.5
[N2] - 0.23
[NH3] - 0.020
A. 0.0035
B. 0.014
C. 0.066
D. 0.017
2 answers
Wouldn't you write the Keq expression, plug in the equilibrium concentrations, and solve for Keq? Post your work if you want someone to check it.
Keq=[NH3]^2/[H2]^2[N2]. Plug in the concentrations for each and you should get 0.014. So the answer is B.
1 answer