Question
Given the equilibrium concentrations in the table, what is the equilibrium constant for the synthesis of ammonia at this temperature?
3H2(g) + N2 <---> 2NH3(g)
[H2] - 0.5
[N2] - 0.23
[NH3] - 0.020
A. 0.0035
B. 0.014
C. 0.066
D. 0.017
3H2(g) + N2 <---> 2NH3(g)
[H2] - 0.5
[N2] - 0.23
[NH3] - 0.020
A. 0.0035
B. 0.014
C. 0.066
D. 0.017
Answers
DrBob222
Wouldn't you write the Keq expression, plug in the equilibrium concentrations, and solve for Keq? Post your work if you want someone to check it.
Dom+Ari
Keq=[NH3]^2/[H2]^2[N2]. Plug in the concentrations for each and you should get 0.014. So the answer is B.