Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Given the reaction: Cu2+(aq) + S2-(aq) CuS(s) What will happen (a) if CuSO4(aq) is added? And (b) if Na2SO4(aq) is added? A. (a...Asked by Laura
                Given the reaction:
Cu2+(aq) + S2-(aq) CuS(s)
What will happen (a) if CuSO4(aq) is added? And (b) if Na2SO4(aq) is added?
A. (a) Nothing; (b) Less product will form
B. (a) Less product will form; (b) Nothing
C. (a) Nothing; (b) More product will form
D. (a) More product will form; (b) Nothing
            
            
        Cu2+(aq) + S2-(aq) CuS(s)
What will happen (a) if CuSO4(aq) is added? And (b) if Na2SO4(aq) is added?
A. (a) Nothing; (b) Less product will form
B. (a) Less product will form; (b) Nothing
C. (a) Nothing; (b) More product will form
D. (a) More product will form; (b) Nothing
Answers
                    Answered by
            DrBob222
            
    Adding CuSO4 is adding a common ion (the Cu^2+) so the reaction will shift to the right producing more CuS. Adding Na2SO4 will do nothing. There is no common ion in Na2SO4 and there is nothing to react. So the answer is ........
    
                    Answered by
            Anonymous
            
    The answer ia to d to some up what they said.
    
                    Answered by
            Dom+Ari
            
    The answer is D.
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.