David Kroell

This page lists questions and answers that were posted by visitors named David Kroell.

Questions

The following questions were asked by visitors named David Kroell.

x is a real number satisfying the equation |x−20|+12=x. What is the value of x?

A right triangle has perimeter equal to 80 and hypotenuse equal to 34. What is the area of the triangle?

Answers

The following answers were posted by visitors named David Kroell.

(2+i)(6−i)=12+6i−2i−i2=12+4i+1=13+4i. Hence the complex part is 4 and the real part is 13.

= (1/2)*PD*AB + (1/2)*PE*BC + (1/2)*PF*AC = (1/2)*AB*(PD + PE + PF) Also, area of triangle ABC = (1/2)*height*AB height = (√3/2)*20√3 = 30 So, PD + PE + PF = height = 30 => PF = 11

Cos^-1 (3/5) = 53 degrees. (This is also close to one radian)

The Buying rate is basically the amount of money people will spend to buy a product. A selling rate is the amount of money that the same person would accept if they sold it to you. Most firms will have a differing Buying and Selling rate in order to make...

I think it refers to thew number of counters that needs to be layer... I'm not sure about that though.

(65 + 84 + 76 + x ) / 4 = 80 (Balance the Equation) 225 + x = 320 [65 + 84 + 76 + x = 320] (Balance the Equation) x = 320 - 225 = 95

I think you mean 11/4 right... Here, I'll help you, but I want you to solve the problem in the end. The key is simplification. You have x+y = 11 ... and x-y = 4 If you put the two equations together you'll get Y. If you submit y into the original equation...

I need to read up on this stuff, and figure out how to solve them.

Nope... I had it wrong... And I know I was a hypocrite there for a sec! :) Solution 1: By componendo and dividendo, we get that (x+y)−(x−y)/(x+y)+(x−y)=11−4/11+4=715. Hence, yx=715, so a+b=22. Solution 2: Since the ratio of x+y to x−y is 114, we can write...

I guess then you had part of it right...

It's 87... I'm not going to explain it... it's complicated... Spend some points and look at the ANSWER OR STUDY THIS TECHNIQUE: Cases (Checking Cases), Recurrence Relation

Thanks! :) I thought it made sense to make it into a quadratic equation. Stupid me... I didn't factorise correctly.

I suppose you mean, 1ab2 in which that line is present over the the set of integers as 1+a+b+2 makes that set of integers. From the rules of divisibility, we want 1+a+b+2 to be a multiple of 3, hence require a+b to be a multiple of 3. a and b can be any o...

John, Brilliant_org is supposed to be a community of learners. If we give you the answer to solve something like this, then we are defeating the purpose of learning. I solved this problem, you can either do it by obtaining it through the lowest common mul...