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Jim has grades of 84, 65, and 76 on three math tests. What grade must he obtain on the next test to have an average of exactly...Asked by Carolyn
jim has grades of 84, 65, 76 on three tests. what grade must he obtain on the next test to have an average of exactly 80% for all four tests?
Answers
Answered by
Ms. Sue
84 + 65 + 76 = 225
0.8 * 400 = 320
320 - 225 = 95
0.8 * 400 = 320
320 - 225 = 95
Answered by
Bosnian
( 84 + 65 + 76 + x ) / 4 = 80
84 + 65 + 76 + x = 4 * 80
225 + x = 320
x = 320 - 225 = 95
84 + 65 + 76 + x = 4 * 80
225 + x = 320
x = 320 - 225 = 95
Answered by
David Kroell
(65 + 84 + 76 + x ) / 4 = 80
(Balance the Equation)
225 + x = 320 [65 + 84 + 76 + x = 320]
(Balance the Equation)
x = 320 - 225 = 95
(Balance the Equation)
225 + x = 320 [65 + 84 + 76 + x = 320]
(Balance the Equation)
x = 320 - 225 = 95
Answered by
johanne laroche
y=5x-3 y=-3x+13
Answered by
Anonymous
The sum of two consecutive numbers is 37. What are they
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