Asked by ayan
What is the real part of (2+i)(6−i)?
Answers
Answered by
David Kroell
(2+i)(6−i)=12+6i−2i−i2=12+4i+1=13+4i.
Hence the complex part is 4 and the real part is 13.
Hence the complex part is 4 and the real part is 13.
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