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Annon
Answers (2)
Part 1: a) ΔH^o = 2ΔH^o (H2O) − 2ΔH^o (H2) − ΔH^o (O2) ΔH^o = (2)(−285.8 kJ/mol) − (2)(0) − (1)(0) = −571.6 kJ/mol Part 2: (b)ΔH^o = 4ΔH^o (CO2) + 2ΔH^o (H2O) − 2ΔH^o (C2H2) − 5ΔH^o (O2) ΔH^o = (4)(−393.5 kJ/mol) + (2)(−285.8
Anna is right stop trying to tell people otherwise I literally just took it and got a 100
