Asked by Annon
a paralelogram has an area of 74 cm^2
side lengths are 9cm x 10 cm
what are the measures of the interir angles of the paralelogram?
i did:
Area=|axb|
74=9(10)sin(angle)
sin^-1(74/90)=angle
angle=55.3 degrees
side lengths are 9cm x 10 cm
what are the measures of the interir angles of the paralelogram?
i did:
Area=|axb|
74=9(10)sin(angle)
sin^-1(74/90)=angle
angle=55.3 degrees
Answers
Answered by
Steve
Looks good to me.
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